In the situation as shown in figure time peri | vedclass

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Question

Let block be displaced through $x$ in downward

direction and elongation in spring $=\mathrm{x}_{1}$ then

$x \cos 	heta=x_{1}$

Vedclass · Accepted Answer

$2\pi \sec 	heta \sqrt {\frac{m}{{2k}}} $

Vedclass · Answer

Let block be displaced through $x$ in downward

direction and elongation in spring $=\mathrm{x}_{1}$ then

$x \cos 	heta=x_{1}$              $...(1)$

Restoring force $\mathrm{F}=2 \mathrm{kx}_{1} \cos 	heta$

$\mathrm{F}=2 \mathrm{k} \cos ^{2} 	heta 	imes$

Hence $\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{2 \mathrm{k} \cos ^{2} 	heta}}=2 \pi \sec 	heta \sqrt{\frac{\mathrm{m}}{2 \mathrm{k}}}$

In the situation as shown in figure time period of vertical oscillation of block for small displacements will be

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